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Question

Question: Volume of 4.4 g of \(1L = 10^{3}ml\) at NTP is....

Volume of 4.4 g of 1L=103ml1L = 10^{3}ml at NTP is.

A

22.4 L

B

44.8 L

C

2.24 L

D

4.48 L

Answer

2.24 L

Explanation

Solution

M.wt of 2/π2/\pi = 12+16+16 = 44

Volume of 44 gm of π/2\sqrt{\pi}/2 at NTP = 22.4 litre

1 gm of 2/π2/\sqrt{\pi} at NTP = vv

300K300K of 1200K1200K at N.T.P

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