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Question: Vertex of the parabola \(x ^ { 2 } + 4 x + 2 y - 7 = 0\)is...

Vertex of the parabola x2+4x+2y−7=0x ^ { 2 } + 4 x + 2 y - 7 = 0is

A

(−2,11/2)( - 2,11 / 2 )

B

(−2,2)( - 2,2 )

C

(−2,11)( - 2,11 )

D

(2,11)( 2,11 )

Answer

(−2,11/2)( - 2,11 / 2 )

Explanation

Solution

Equation of the parabola is (x+2)2=−2y+7+4( x + 2 ) ^ { 2 } = - 2 y + 7 + 4⇒ (x+2)2=−2(y−112)( x + 2 ) ^ { 2 } = - 2 \left( y - \frac { 11 } { 2 } \right). Hence vertex is (−2,112)\left( - 2 , \frac { 11 } { 2 } \right)