Question

Velocity time graph of a particle in motion is shown. Then displacement and distance covered by the particle in 2 seconds

• A. 2,4 m
• B. 0,2 m
• C. 2,2 m
• D. 0,0 m

Answer 1

Answer: (B)

0,2 m

Answer 2

Displacement is the signed area under the v-t graph. From $t=0$ to $t=1$, area = $\frac{1}{2} \times 1 \times 2 = 1$ m. From $t=1$ to $t=2$, area = $\frac{1}{2} \times 1 \times (-2) = -1$ m. Total displacement = $1 + (-1) = 0$ m. Distance is the sum of absolute areas: $|1| + |-1| = 2$ m.