Solveeit Logo

Question

Physics Question on Work-energy theorem

Velocity of a particle of mass m as a function of displacement x is given by v = ɑ√x. Work done to move it from x = 0 to x = d is:

A

ma22d\frac{ma^2}{2}\cdot d

B

ma2dma^2\cdot d

C

3ma2d23ma^2\cdot \frac{d}{2}

D

2ma2d2ma^2\cdot d

Answer

ma22d\frac{ma^2}{2}\cdot d

Explanation

Solution

The Correct answer is option is (A) : ma22d\frac{ma^2}{2}\cdot d