Question

Velocity at mean position of a particle executing S.H.M. is v, they velocity of the particle at a distance equal to half of the amplitude

• A. 4v
• B. 2v
• C. $\frac{\sqrt{3}}{2}v$
• D. $\frac{\sqrt{3}}{4}v$

Answer 1

Answer: (C)

$\frac{\sqrt{3}}{2}v$

Answer 2

Velocity in mean position $v = a\omega,$ velocity at a distance of half amplitude.

$v^{'} = \omega\sqrt{a^{2} - y^{2}} = \omega\sqrt{a^{2} - \frac{a^{2}}{4}} = \sqrt{\frac{3}{2}}a\omega = \sqrt{\frac{3}{2}}v$