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Question

Physics Question on work, energy and power

Vectors ai^+bj^+k^a \hat{i}+b \hat{j}+\hat{k} and 2i^3j^+4k^2 \hat{i}-3 \hat{j}+4 \hat{k} are perpendicular to each other when 3a+2b=73 a+2 b=7, the ratio of aa to bb is x2\frac{x}{2} The value of xx is __

Answer

The correct answer is 1.
For two perpendicular vectors
(ai^+bj^​+k^)⋅(2i^−3j^​+4k^)=0
2a−3b+4=0
On solving, 2a−3b=−4
Also given
3a+2b=7
We get a=1,b=2
ba​=2x​⇒x=b2a​=22×1​
⇒x=1