Question

Vapour pressure of $\mathrm { CCl } _ { 4 }$ at is 143 mm of $H g 0.5 \mathrm { gm }$ of a non-volatile solute (mol. wt. = 65) is dissolved in $100 \mathrm { ml } \mathrm { CCl } _ { 4 }$ . Find the vapour pressure of the solution (Density of ).

• A.
• B. 94.39 mm
• C. 199.34 mm
• D.

Answer 1

Answer: (A)

Answer 2

$\frac { P ^ { 0 } - P s } { P ^ { 0 } } = \frac { w \times M } { m W }$ $= 143 - \frac { 0.5 \times 154 } { 65 \times 158 } \times 143$

$= 143 - 1.03 = 141.97 \mathrm {~mm}$.