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Chemistry Question on Solutions

Vapour pressure of dilute aqueous solution of glucose is 750 mm750\, mm of mercury at 373 K373\, K. The mole fraction of solute is

A

176\frac{1}{76}

B

17.6\frac{1}{7.6}

C

138\frac{1}{38}

D

110\frac{1}{10}

Answer

176\frac{1}{76}

Explanation

Solution

At 373 K(100∘C)373\, K \left(100^{\circ} C \right) V.P.
of water, p∘=760 mm Hg,ps=750 mm Hgp ^{\circ}=760\, mm\,Hg , p_{s}=750\, mm\,Hg
p∘−psp∘=xB\frac{p^{\circ}-p_{s}}{p^{\circ}}=x_{B}
760−750760=xB\frac{760 -750}{760}=x_{B}
xB=176x_{B}=\frac{1}{76}