Question

Vapour density of $PCl_5$ is $104.16$ but when heated to $230^{\circ} C$ its vapour density is reduced to 62. The degree of dissociation of $PCl_5$ at this temperature will be

• A. 0.068
• B. 0.68
• C. 0.46
• D. 0.64

Answer 1

Answer: (B)

0.68

Answer 2

${PCl_5(g) <=> PCl_3 (g) + Cl_2(g)}$ Here $y =2$ $x = \frac{D -d}{d(y-1)} = \frac{104.16 - 62}{62}$ = 0.68 = 68 %