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Question: Vapour density of a volatile substance is\(1.2\)(\({C_2}{H_6} = 1\)).Its molecular mass would be____...

Vapour density of a volatile substance is1.21.2(C2H6=1{C_2}{H_6} = 1).Its molecular mass would be_______
(A) 1.21.2
(B) 2.42.4
(C) 3636
(D) 7272

Explanation

Solution

Vapour density is defined as the mass of the certain volume of a substance divided by mass of the same volume of hydrogen. It has no units. Vapour density is found out by dividing the molecular mass of a substance by two. The molecular mass can be found out by this equation.

Complete step-by-step answer: We know that vapour density is the molecular mass divided by two.
We know that molar mass = 2×2 \times vapour density
Molar mass of ethane = 3030 gm
Therefore, vapour density= 302=15\dfrac{{30}}{2} = 15
Relative vapour density is 1.21.2 for ethane
Therefore Vapour density= 15×1.2=1815 \times 1.2 = 18
Hence the molar mass of substance =18×2=36 = 18 \times 2 = 36
So the molar mass of the substance is thirty six.

Therefore the correct answer is option C.

Note: Vapour density is the ratio of mass of the volume of the gas to the mass of an equal volume of hydrogen . It is measured under the same conditions of temperature and pressure.