Question

Van't Hoff factors of equimolal solutions of sodium chloride, barium chloride and glucose in water are

• A. $2, 3, 0$ respectively
• B. $2, 3, 6$ respectively
• C. $2, 3, 4$ respectively
• D. $2, 3, 1$ respectively

Answer 1

Answer: (D)

$2, 3, 1$ respectively

Answer 2

${NaCl_{(aq)} -> Na^{+}_{(aq)} + Cl^{-}_{(aq)}}$
van't Hoff factor, $i = 2$
${ BaCl_{2(aq)} -> Ba^{2+}_{(aq)} + 2 Cl^{-}_{(aq)}} ,i = 3$
Glucose does not undergo dissociation or association hence, $i = 1$.