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Question

Chemistry Question on States of matter

van der Waals equation for one mole of CO2CO_2 gas at low pressure will be

A

(P+aV2)V=RT\left(P+\frac{a}{V^{2}}\right)V=RT

B

P(Vb)=RTaV2P\left(V-b\right)=RT-\frac{a}{V^{2}}

C

P=RTVbP=\frac{RT}{V-b}

D

P=(RTVbaV2)P=\left(\frac{RT}{V-b}-\frac{a}{V^{2}}\right)

Answer

(P+aV2)V=RT\left(P+\frac{a}{V^{2}}\right)V=RT

Explanation

Solution

van der Waals equation for one mole of CO2CO_2 gas is [P+aV2][Vb]=RT\left[P+\frac{a}{V^{2}}\right]\left[V-b\right] = RT At low pressure, VV is high hence (Vb)V(V - b) \approx V. (P+aV2)V=RT\therefore\left(P+\frac{a}{V^{2}}\right)V = RT