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Question

Chemistry Question on States of matter

Van der Waal's equation for a gas is stated as, p=nRTVnba(nV)2.p = \frac{nRT}{V-nb}-a\left(\frac{n}{V}\right)^{2}. This equation reduces to the perfect gas equation, p=nRTVp = \frac{nRT}{V} when ,

A

temperature is sufficiently high and pressure is low

B

temperature is sufficiently low and pressure is high

C

both temperature and pressure are very high

D

both temperature and pressure are very low

Answer

temperature is sufficiently high and pressure is low

Explanation

Solution

Van der waal equation:
(p+an2v2)(vnb)=nRT\left(p+\frac{a n^{2}}{v^{2}}\right)(v-n b)=n R T
or,
P=nRTvnba(nv)2P=\frac{n R T}{v-n b}-a\left(\frac{n}{v}\right)^{2}
where, v is volume
PP is pressure
TT is Temperature
nn is mole of gas
RR is universal gas constant.
the ideal gas equation works well when intermolecular attractions between gas molecular are negligible and the gas molecules themselves do not occupy a significant part of the whole volume. This is usually true when the pressure is low and the temperature is high.