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Chemistry Question on Standard electrode potentials and electrochemical cells

Values of ϵ0\epsilon^0 Reduction are given below as:-
Sn2+∣Sn=−0.14V,Zn2+∣Zn=−0.76V,Cr3+∣Cr=−0.74V\Mg2+∣Mg=−2.36VSn^{2+} |Sn = -0.14V, Zn^{2+} |Zn = -0.76V, Cr^{3+} |Cr = -0.74V\\\Mg^{2+} | Mg = -2.36V
The ion which will get deposited at cathode in an electrochemical cell would be

A

Sn2+Sn^{2+}

B

Zn2+Zn^{2+}

C

Cr3+Cr^{3+}

D

Mg2+Mg^{2+}

Answer

Sn2+Sn^{2+}

Explanation

Solution

The correct option is (A): Sn2+