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Question: Value of the parameter 'a' such that area bounded by y = x<sup>2</sup>− 3 and the line y = ax + 2, a...

Value of the parameter 'a' such that area bounded by y = x2− 3 and the line y = ax + 2, attains it's minimum value is

A

-1

B

1

C

0

D

None of these

Answer

0

Explanation

Solution

The lines y = ax + 2 are concurrent at (0, 2). Thus bounded area is minimum provided a = 0. Because the area tend to increase if we take 'a' to be negative or positive