Question
Mathematics Question on Exponential and Logarithmic Functions
Value of [(logba)(logcb)(logac)] is
A
0
B
1
C
abc
D
log abc
Answer
1
Explanation
Solution
(logb a) (logcb)(logac) =logbloga×logclogb×logalogc[∵logmn=logmlogn] =1
Value of [(logba)(logcb)(logac)] is
0
1
abc
log abc
1
(logb a) (logcb)(logac) =logbloga×logclogb×logalogc[∵logmn=logmlogn] =1