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Question: Value of \(\int _ { 1 / e } ^ { e } \frac { \mathrm { dt } } { \mathrm { t } ^ { 3 } + \mathrm { t ...

Value of ∫1/eedtt3+t\int _ { 1 / e } ^ { e } \frac { \mathrm { dt } } { \mathrm { t } ^ { 3 } + \mathrm { t } } is equal to

A

1e2+1\frac { 1 } { \mathrm { e } ^ { 2 } + 1 }

B

e2 – 1

C

– 1

D

1

Answer

1

Explanation

Solution

I =

=