Question
Question: Value of dissociation constant of acetic acid is \({{10}^{-6}}\), whereas dissociation constant of f...
Value of dissociation constant of acetic acid is 10−6, whereas dissociation constant of formic acid is 10−5. Which of the following will be the value of pKa(acetic acid) - pKa(formic acid)?
Solution
Write down the dissociation of the base in water. Find the equilibrium constant for the dissociation process with the degree of dissociation. The formula for equilibrium constant is given below. Kb will be equal to the equilibrium constant calculated.
Formula: Kc=ConcentrationnofreactantsConcentrationnofproducts
Complete step-by-step answer:
We will write the dissociation of acetic acid as well as of formic acid.
Acetic acid : CH3COOH → H+ + CH3COO−
Formic acid : HCOOH → H+ + HCOO−
The values of dissociation constant have already been given to us. The symbol for dissociation constant is Ka.
pKa stands for negative log of Ka.
We will now calculate the pKa of acetic acid and formic acid.
Acetic acid:
Ka = 10−6
pKa = −log(Ka) = 6
Formic acid:
Ka = 10−5
pKa = −log(Ka) = 5
The value of pKa(acetic acid) - pKa(formic acid) = 6 - 5 = 1.
Therefore, the correct answer is option (B).
Note: pKa numerically denotes the concentration of hydrogen ions in a solution. pH stands for potenz of hydrogen and indicates the amount of H+ ions present. pKa is the pH of the solution when the concentration of acid is greater than the concentration of hydrogen ions in water i.e. 10−7. However, when the concentration of acid is lesser than that of acid, we have to include the concentration of hydrogen ions present in water as well in order to find the pH of the solution.