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Question

Physics Question on kinetic theory

vrms,vavv_{rms} , v_{av} and vmpv_{mp} are root mean square, average and most probable speeds of molecules of a gas obeying Maxwellian velocity distribution. Which of the following statements is correct?

A

vrms<vav<vmpv_{ rms } < v_{ av } < v_{ mp }

B

vrms>vav>vmpv_{ rms }>v_{ av }>v_{ mp }

C

vmp<vrms<vavv_{ mp } < v_{ rms } < v_{ av }

D

vmp>vrms>vavv_{ mp }>v_{ rms }>v_{ av }

Answer

vrms>vav>vmpv_{ rms }>v_{ av }>v_{ mp }

Explanation

Solution

Root mean square speed. The root mean square speed is used to measure the velocity of particles in a gas. It is given by vrms=3RTM=1.732RTMv_{ rms }=\sqrt{\frac{3 R T}{M}}=1.732 \sqrt{\frac{R T}{M}} ... (1) where MM is molar mass and RR is gas constant, TT is temperature. Most probable speed vpv_{ p }, is the speed most likely to be possessed by any molecule in the system. vav=2RTM=1.41RTMv_{ av }=\sqrt{\frac{2 R T}{M}}=1.41 \sqrt{\frac{R T}{M}} ... (2) whereas mean speed is vmp=8RTπM=1.6RTMv_{ mp }=\sqrt{\frac{8 R T}{\pi M}}=1.6 \sqrt{\frac{R T}{M}} ... (3) From Eqs. (1), (2) and (3), we conclude that Vrms>Vav>VmpV_{rms} > V_{av} > V_{mp}