Using valence bond theory, the complex (\lbrack Cr(H\_{2}O)\... | CHEMISTRY - BONDING IN COORDINATION COMPOUNDS & HYBRIDIZATION AND GEOMETRY | SolveeIt | Solveeit

Today, October 4

Question

Using valence bond theory, the complex $\lbrack Cr(H_{2}O)_{6}\rbrack^{3 +}$ can be described as

A

$sp^{3}d^{2}$ , outer orbital complex, paramagnetic

B

$dsp^{2},$ inner orbital complex, diamagnetic

C

$d^{2}sp^{3}$ , inner orbital complex, paramagnetic

D

$d^{2}sp^{3},$ outer orbital complex, diamagnetic

Answer

$d^{2}sp^{3}$ , inner orbital complex, paramagnetic

Explanation

Solution

In $\lbrack Cr(H_{2}O)_{6}\rbrack^{3 +}$ , Oxidations state of Cr = +3, $Cr^{3 +} = 3d^{3}$

It is an inner orbital complex. Due to presence of three unpaired electrons, it is paramagnetic.