Question

Using the given figure, the ratio of R₁ values of sample A and sample C is $x \times 10^{-2}$.Value of x is

Answer 1

50

Answer 2

The $R_f$ value is calculated as the ratio of the distance traveled by the substance to the distance traveled by the solvent front from the origin (base line). $R_{f,A} = \frac{\text{Distance traveled by Sample A}}{\text{Distance traveled by solvent front}} = \frac{5.0 \text{ cm}}{12.5 \text{ cm}} = 0.4$ $R_{f,C} = \frac{\text{Distance traveled by Sample C}}{\text{Distance traveled by solvent front}} = \frac{10.0 \text{ cm}}{12.5 \text{ cm}} = 0.8$ The ratio of $R_f$ values of sample A and sample C is $\frac{R_{f,A}}{R_{f,C}} = \frac{0.4}{0.8} = 0.5$. We are given that this ratio is $x \times 10^{-2}$. So, $0.5 = x \times 10^{-2}$. Solving for $x$: $x = \frac{0.5}{10^{-2}} = 0.5 \times 10^2 = 50$.