Question

Using the data given below and find the out in which option the order of reducing power in correct.

$Eº_{CrO_{7}^{2 -}/Cr^{3 +}} = 1.33V;Eº_{Cl_{2}/Cl} = 1.36V$

$Eº_{MnO_{4}^{-}/Mn^{2 +}} = 1.51V;Eº_{Cr^{3 +}/Cr} = - 0.74V$

• A. $Cr^{3 +} < Cl^{-} < Mn^{2 +} < Cr$
• B. $Mn^{2 +} < Cl^{-} < Cr^{3. +} < Cr$
• C. $Cr^{3 +} < Cl^{-} < Cr_{2}O_{7}^{2 -} < MnO_{4}^{-}$
• D. $Mn^{2 +} < Cr^{3 +} < Cl^{-} < Cr$

Answer 1

Answer: (B)

$Mn^{2 +} < Cl^{-} < Cr^{3. +} < Cr$

Answer 2

Lower the reduction potential higher is the reducing power.

$Mn^{2 +} < Cl^{-} < Cr^{3 +} < Cr$