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Chemistry Question on Chemical bonding and molecular structure

Using MOT, compare O2+O_2^+ and O2−O_2^- species and choose the incorrect option.

A

O2+O _2^+ have higher bond order than O2−O_2^- .

B

O2−O _2^- is less stable

C

O2+O _2^+ is diamagnetic while O2−O _2^- is paramagnetic

D

Both O2+O _2^+ and O2−O _2^- are paramagnetic.

Answer

O2+O _2^+ is diamagnetic while O2−O _2^- is paramagnetic

Explanation

Solution

Key concept Molecules or ions having odd number of electrons are paramagnetic in nature.

O2+O_2^+ ion electronic configuration:

σ1s2,σ?,1s2,σ?2s2,σ2pz2,\sigma1s^{2}, \sigma^{ ? },1s^{2},\sigma^{ ? }2s^{2},\sigma2p_{z^{^2}},
{π2px2 π2py2}{? π2px1 ? π2py}? σ2pz\quad\quad\quad\quad\quad\quad\begin{Bmatrix}\pi2p_{x^{2}}\\\ \pi2p_{y^{2}}\end{Bmatrix}\begin{Bmatrix}?\quad\quad\\\ \pi2p_{x^{1}}\\\ ?\quad\quad\\\ \pi2p_{y}\end{Bmatrix}\begin{matrix}?\quad\quad\\\ \sigma2p_{z}\end{matrix}

Total number of electrons 16 - 1 = 15

It is paramagnetic

Bond order = 10−52=25\frac{10-5}{2} = 25 (more stable)

O2−O_{2}^{-} ion electronic configuration

σ1s2,?σ1s2,σ2s2,?σ2s2,σ2pz2,\sigma1s^{2},^{ ? }\sigma1s^{2},\sigma2s^{2},^{ ? }\sigma2s^{2},\sigma2p^{2}_{z},
{π2px2 π2py2}{? π2px1 ? π2py}? σ2pz\quad\quad\quad\quad\quad\quad\begin{Bmatrix}\pi2p_{x^{2}}\\\ \pi2p_{y^{2}}\end{Bmatrix}\begin{Bmatrix}?\quad\quad\\\ \pi2p_{x^{1}}\\\ ?\quad\quad\\\ \pi2p_{y}\end{Bmatrix}\begin{matrix}?\quad\quad\\\ \sigma2p_{z}\end{matrix}

Total number of electrons = 16 + 1 = 17

It is paramagnetic.

Bond order = 10−77=32=1.5\frac{10-7}{7}=\frac{3}{2} = 1.5 (less stable)