Question
Question: Using a logarithm table, determine the value of \(\log _{10}^{0.5432}\). (A) \(\overline 1 .7350\)...
Using a logarithm table, determine the value of log100.5432.
(A) 1.7350
(B) 2.7350
(C) 0.7350
(D) 0.07350
Solution
We have to find the value of log100.5432 using logarithm table. By using a logarithm table we have to first calculate the mantissa and characteristics of 0.5432. And then we have to calculate the sum of characteristics and the mantissa, which is the value of log100.5432.
Complete step by step answer:
Here, we have to determine the value of log100.5432 using a logarithm table.
Firstly, write 0.5432 such that one non zero digit is before the decimal point, this imply
0.5432=5.432×10−1
Now we have to determine the mantissa of 0.5432.
Mantissa is calculated by seeing the value corresponding to 52 in the row and corresponding to 3 in the column and then add the value corresponding to 2 in the mean difference table.
Following above written points we get a mantissa of 0.5432 is 0.7350.
Now, find the characteristics of 0.5432
Characteristics of 0.5432 can be evaluated by using log1010−1.
Thus, characteristics of 0.5432 is −1.
The value of log100.5432=mantissa + characteristics
⇒log100.5432=0.7350+(−1) ⇒log100.5432=1.7350
So, the correct answer is Option A.
Note: Procedure to find the value log10x using logarithm table.
1.write the given number xsuch that one non zero number comes before the decimal. To convert in this form multiply by 10n where n is a suitable number i.e x=y×10n.
2.Take the first two digits of the number y and match the value corresponding to this in the row and third digit in the column and then add this value to the value given corresponding to the fourth digit of the given number y from the mean difference table. This will be the mantissa part.
3.Find a characteristic using formula log1010n=n.
4.Add the mantissa and characteristics of the given number x to find the value of log10x.