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Question: Using a bar magnet P, a vibration magnetometer has time period 2seconds. When a bar Q (identical to ...

Using a bar magnet P, a vibration magnetometer has time period 2seconds. When a bar Q (identical to P in mass and size) is placed on top of P, the time period is unchanged. Which of the following statements is true

A

Q is of non-magnetic material

B

Q is a bar magnet identical to P, and its north pole placed on top of P's North Pole

C

Q is of unmagnetized ferromagnetic material

D

Nothing can be said about Q's properties

Answer

Q is a bar magnet identical to P, and its north pole placed on top of P's North Pole

Explanation

Solution

T=2πIMBHT = 2 \pi \sqrt { \frac { I } { M B _ { H } } }. If Q is an identical bar magnet then time period of system will be T=2π2I(2M)BH=TT ^ { \prime } = 2 \pi \sqrt { \frac { 2 I } { ( 2 M ) B _ { H } } } = T