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Question

Physics Question on The speed of a travelling wave

Use the formula v=γpρv=\sqrt\frac{γp}{ρ} to explain why the speed of sound in air

(a) is independent of pressure,

(b) increases with temperature,

(c) increases with humidity.

Answer

Take the relation:

v=γpρv=\sqrt\frac{γp}{ρ} ........(i)........(i)

Where,

Density, ρ =MassVolume=MV=\frac{Mass}{Volume}=\frac{M}{V}

M= Molecular weight of that gas

v= Volume of the gas

Hence, equation (i) reduces to:

v=γPvMv=\sqrt \frac{γPv}{M} ........(ii)........(ii)

Now from the ideal gas equation for n = 1:

PV = RT

For constant T, PV = Constant

Since both M and γ are constants, v = Constant

Hence, at a constant temperature, the speed of sound in a gaseous medium is independent of the change in the pressure of the gas.

Take the relation:

v=γPρv=\sqrt \frac{γP}{ρ} ........(i)........(i)

For one mole of an ideal gas, the gas equation can be written as:

PV = RT

p=RTVp=\frac{RT}{V} ........(ii)........(ii)

Substituting equation (ii) in equation (i), we get:

v=γRTVρ=γRTMv=\sqrt \frac{γRT}{Vρ}=\sqrt \frac{γRT}{M} ........(iv)........(iv)

Where,

Mass, M = ρV is a constant

γ and R are also constants

We conclude from equation (iv) that . vTv∝\sqrt{T}.

Hence, the speed of sound in a gas is directly proportional to the square root of the temperature of the gaseous medium, i.e., the speed of the sound increases with an increase in the temperature of the gaseous medium and vice versa.

Let vmandvdv_m\,and\,v_d be the speeds of sound in moist air and dry air respectively.

Let ρmandρdρ_m\,and\,ρ_d be the densities of moist air and dry air respectively

Take the relation:

v=γPρv=\sqrt \frac{γP}{ρ}

Hence, the speed of sound in moist air is:

vm=γPρmv_m=\sqrt \frac{γP}{ρ_m} ........(i)........(i)

And the speed of sound in dry air is

vd=γPρdv_d=\sqrt \frac{γP}{ρ_d} ........(ii)........(ii)

On dividing equations (i) and (ii), we get:

vdvd=γPρmPdyρ=pdpm\frac{v_d}{v_d}=\sqrt \frac{γP}{ρ_m}* \frac{P_d}{y_ρ}=\sqrt\frac{p_d}{p_m}

However, the presence of water vapour reduces the density of air, i.e.,

ρd<pm

∴ vm>vd

Hence, the speed of sound in moist air is greater than it is in dry air. Thus, in a gaseous medium, the speed of sound increases with humidity.