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Question: Use the data given in the following table to calculate the molar mass of naturally occurring argon i...

Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes:

IsotopeIsotopic molar massAbundance
36Ar{}^{36}Ar35.96755gmol135.96755gmo{l^{ - 1}}0.337%0.337\%
38Ar{}^{38}Ar37.96272gmol137.96272gmo{l^{ - 1}}0.063%0.063\%
40Ar{}^{40}Ar39.9624gmol139.9624gmo{l^{ - 1}}99.6%99.6\%
Explanation

Solution

Atomic mass is the total mass of protons and neutrons. An atomic number is the number of protons in the nucleus of an atom. Isotopes: Those elements which have the same atomic number but different atomic mass. For example: C12C - 12 and C13C - 13 . They both have the same atomic number i.e. 66 but different atomic mass i.e. in C12C - 12 mass is 1212 and in C13C - 13 mass is 1313 .

Complete step by step solution:
First of all let us talk about isotopes and isobars.
Atomic mass: It is defined as the total number of protons and neutrons present in the nucleus of an atom. It is represented by symbol A.
Atomic number: It is defined as the number of protons in the nucleus of an atom. It is represented by symbol Z.
Isotopes: Those elements which have the same atomic number but different atomic mass. For example: C12C - 12 and C13C - 13 . They both have the same atomic number i.e. 66 but different atomic mass i.e. in C12C - 12 mass is 1212 and in C13C - 13 mass is 1313 .
Isobars: Those elements which have the same atomic mass but different atomic numbers. For example: argon and calcium. The atomic number of argon is 1818 and that of calcium is 2020 but the atomic mass of both the elements is the same i.e. 4040 .
Here we are given with the isotopes of argon. And the atomic masses of these isotopes are 36,3836,38 and 4040 .
Now the molar mass of the element is calculated by the sum of the product of atomic mass of the isotopes to its abundance divided by 100100 .
So molar mass of argon will be 36Ar×abundance+38Ar×abundance+40Ar×abundance100\dfrac{{{}^{36}Ar \times abundance + {}^{38}Ar \times abundance + {}^{40}Ar \times abundance}}{{100}} .
Molar mass 36×0.337+38×0.063+40×99.60100=39.98gmol1\dfrac{{36 \times 0.337 + 38 \times 0.063 + 40 \times 99.60}}{{100}} = 39.98gmo{l^{ - 1}} ,
Hence, the molar mass of naturally occurring argon isotopes is 39.98gmol139.98gmo{l^{ - 1}} .

Note:
Vapour density is defined as the density of a gas or substance relative to hydrogen at the same temperature and pressure i.e. mass of substance in a certain volume divided by the mass of hydrogen gas at the same volume.