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Question: Use the data given below and find out the most stable ion in its reduced form. \[Eº_{CrO_{7}^{2 -}/...

Use the data given below and find out the most stable ion in its reduced form.

EºCrO72/Cr3+=1.33V;EºCl2/Cl=1.36VEº_{CrO_{7}^{2 -}/Cr^{3 +}} = 1.33V;Eº_{Cl_{2}/Cl} = 1.36V

EºMnO4/Mn2+=1.51V;EºCr3+/Cr=0.74VEº_{MnO_{4}^{-}/Mn^{2 +}} = 1.51V;Eº_{Cr^{3 +}/Cr} = - 0.74V

A

ClCl^{-}

B

Cr3+Cr^{3 +}

C

CrCr

D

Mn2+Mn^{2 +}

Answer

Mn2+Mn^{2 +}

Explanation

Solution

EºMnO4Mn2+E{º_{MnO_{4}^{-}}}_{|Mn^{2 +}} has highest reduction potential hence, Mn2+Mn^{2 +}is the most stable reduced species.