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Question

Chemistry Question on Thermodynamics

Unit of entropy is

A

JK−1mol−1JK ^{-1} mol ^{-1}

B

J mol−1J\, mol ^{-1}

C

J−1K−1mol−1J^{-1} K ^{-1} mol ^{-1}

D

JKmol−1JK mol ^{-1}

Answer

JK−1mol−1JK ^{-1} mol ^{-1}

Explanation

Solution

ΔS=qT\Delta S=\frac{q}{T} q=q= required heat per molm o l T=T= constant absolute temperature. Unit of entropy is JK−1mol−1J K^{-1} mol ^{-1}