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Question

Physics Question on Electromagnetic induction

Uniform magnetic field exists in region given by B=3i+4j+5k . A rod of length 5 m is placed along y - axis is moved along x axis with constant speed 1 m/sec. Then the magnitude of induced e.m.f in the rod is :

A

zero

B

25 volt

C

20 volt

D

15 volt

Answer

25 volt

Explanation

Solution

Given: B=3i^+4j^+5k^\vec{ B }=3 \hat{ i }+4 \hat{ j }+5 \hat{ k } Length of rod l=5j^\vec{ l }=5 \hat{ j } Velocity of rod v=1i^\vec{ v }=1 \hat{ i } Induced emf is given by E=(v×B)lE =(\vec{ v } \times \vec{ B }) \cdot \vec{ l } E=(1i^×(3i^+4j^+5k^)](5j^)\therefore E =(1 \hat{ i } \times(3 \hat{ i }+4 \hat{ j }+5 \hat{ k })] \cdot(5 \hat{ j }) Or E=(4k^5j^)(5j^)=25E =(4 \hat{ k }-5 \hat{ j }) \cdot(5 \hat{ j })=-25 volts E=25\vec| E |=25 volts