Question

$\underset { \text { Sucrose } } { \mathrm { C } _ { 12 } \mathrm { H } _ { 22 } \mathrm { O } _ { 11 } } + \mathrm { H } _ { 2 } \mathrm { O } \xrightarrow { \text { W. } \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } } \underset { \text { Fractose } } { \mathrm { C } _ { 6 } \mathrm { H } _ { 12 } \mathrm { O } _ { 6 } ( \mathrm { aq } ) } + \underset { \text { Glucose } } { \mathrm { C } _ { 6 } \mathrm { H } _ { 12 } \mathrm { O } _ { 6 } ( \mathrm { aq } ) }$

In this reaction, dilute $\mathrm { H } _ { 2 } \mathrm { SO } _ { 4 }$ is called.

• A. Homogeneous catalysis
• B. Homogeneous catalyst
• C. Heterogeneous catalysis
• D. Heterogeneous catalyst

Answer 1

Answer: (B)

Homogeneous catalyst

Answer 2

Because reactant and catalyst are present in same physical state.