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Question

Chemistry Question on Thermodynamics

Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant externalpressureof2bar Theworkdonebythe gas i s : [Given that 1Lbar= 100J)

A

25 J

B

30 J

C

- 30J

D

5 kJ

Answer

- 30J

Explanation

Solution

  Wirr=PextΔV\therefore \; W_{irr} = - P_{ext } \Delta V
= - 2 bar ×\times (0.25 - 0.1) L
= - 2 ×\times 0.15 L-bar
= - 0.30 L-bar
= - 0.30 ×\times 100 J
= - 30 J