Question
Question: Under identical conditions of pressure and temperature, 4L of gaseous mixture ( \({H_2}\) and \(C{H_...
Under identical conditions of pressure and temperature, 4L of gaseous mixture ( H2 and CH4 ) effuses through a hole in 5 min whereas 4L of a gas X of molecular mass 36 takes 10 min to effuse through the same hole. The mole ratio of H2:CH4 in the mixture is:
A. 1:3
B. 1:2
C. 2:3
D. 1:1
Solution
Basically, effusion is the ability of a gas to escape or travel through a small hole with a small aperture and from a place of high concentration to low concentration. Generally, this is a process that happens every day in our lives.
Formula used:
Time αmolecularweight
Molecular weight m1=n1+n2n1M1+n2M2
Where n1 and n2 are the number of moles of H2 and CH2 respectively.
Complete step by step answer:
Basically effusion in simple words is the ability of gas to travel through a small opening. It occurs when the size of the aperture of hole is smaller than the mean free path of the molecules. It generally occurs or is facilitated by a difference of pressures.
Now, we have to calculate the mole ratio of H2:CH4 in the mixture.
So, rate of diffusion is directly proportional to molecularweight1
Therefore, time αmolecularweight
Now, we have been given that the time taken for a mixture is 5minwhereas the time taken for unknown gas is 10min.
So, =1036
Which means, m1=3
Therefore, m1=9
Now, according to the formula
Molecular weight m1=n1+n2n1M1+n2M2
Now, substitute the value,
9=(n1+n2)n1×2+n2×16
So, 9n1+9n2=2n1+16n2
7n1=n2
Therefore, n1=n2
So, the mole ratio is 1:1
Hence, option D is correct.
Note:
Don’t get confused with diffusion and effusion. These two terms are nothing but two different properties of gases. Diffusion is the ability of gases to mix with each other without requiring bulk motion whereas effusion is the ability of gas to escape or travel through a small hole with a small aperture.