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Question: Uncertainty in position of a 0.25 *g* particle is \(10^{- 5}\). Uncertainty of velocity is \((h = 6....

Uncertainty in position of a 0.25 g particle is 10−510^{- 5}. Uncertainty of velocity is (h=6.6×10−34Js)(h = 6.6 \times 10^{- 34}Js)

A

1.2×10341.2 \times 10^{34}

B

2.1×10−292.1 \times 10^{- 29}

C

1.6×10−201.6 \times 10^{- 20}

D

1.7×10−91.7 \times 10^{- 9}

Answer

2.1×10−292.1 \times 10^{- 29}

Explanation

Solution

According to Δx 6mu×m 6mu×Δv=h4π\Delta x\mspace{6mu} \times m\mspace{6mu} \times \Delta v = \frac{h}{4\pi}; Δv=hΔx 6mu×m 6mu×4π\Delta v = \frac{h}{\Delta x\mspace{6mu} \times m\mspace{6mu} \times 4\pi}

=6.6×10−3410−5×0.25×3.14×4=2.1×10−29 6mu 6mum/s= \frac{6.6 \times 10^{- 34}}{10^{- 5} \times 0.25 \times 3.14 \times 4} = 2.1 \times 10^{- 29}\mspace{6mu}\mspace{6mu} m/s