Question

Find the strength of the magnetic field in a conductor 0.5m long moving with a velocity of 10m/s, inducing an eml of 20V if magnetic field, velocity and length of conductor are mutually perpendicular to each other.

• A. 0 21
• B. 0 14T
• C. 0 11
• D. 0 4T

Answer 1

Answer: (D)

4T

Answer 2

The problem asks us to find the strength of the magnetic field (B) given the induced electromotive force (EMF), the length of the conductor, and its velocity. The problem states that the magnetic field, velocity, and length of the conductor are mutually perpendicular.

The formula for motional EMF ($\varepsilon$) when the magnetic field (B), the length of the conductor (L), and the velocity (v) are mutually perpendicular is:

$\varepsilon = B L v$

We are given:

Induced EMF ($\varepsilon$) = 20 V Length of the conductor (L) = 0.5 m Velocity of the conductor (v) = 10 m/s

We need to find the magnetic field strength (B). Rearranging the formula to solve for B:

$B = \frac{\varepsilon}{L v}$

Now, substitute the given values into the formula:

$B = \frac{20 \, \text{V}}{0.5 \, \text{m} \times 10 \, \text{m/s}}$ $B = \frac{20 \, \text{V}}{5 \, \text{m}^2/\text{s}}$ $B = 4 \, \text{T}$

Thus, the strength of the magnetic field is 4 Tesla.