Question
Question: Simplify: $\frac{log_3 512}{log_3 8} \times \frac{log_3 3}{log_3 9} | \frac{log_3 3}{log_3 4} + \fra...
Simplify: log38log3512×log39log33∣log34log33+log34log33

43log34
Solution
The problem asks to simplify the given logarithmic expression. The expression is: log38log3512×log39log33log34log33+log34log33 The symbol ' | ' is unconventional in this context. Assuming it represents division, the expression can be written as: log38log3512×log39log33÷(log34log33+log34log33) We will simplify each part of the expression using logarithm properties:
- Change of Base Formula: logbclogba=logca
- Power Rule: logb(ak)=klogba
- Identity: logbb=1
Step 1: Simplify the first fraction log38log3512 Using the change of base formula, this is equivalent to log8512. Since 83=512, we have log8512=3.
Step 2: Simplify the second fraction log39log33 Using the identity log33=1 and the power rule for log39: log39=log3(32)=2log33=2×1=2. So, the fraction becomes 21.
Step 3: Simplify the terms inside the parenthesis log34log33+log34log33 Since log33=1, each term is log341. So, the sum is log341+log341=log342.
Step 4: Substitute the simplified terms back into the main expression The expression now becomes: 3×21÷(log342)
Step 5: Perform the multiplication and division 23÷log342 To divide by a fraction, multiply by its reciprocal: 23×2log34 43log34
Step 6: Further simplification (optional) We can express log34 in terms of log32: log34=log3(22)=2log32. Substitute this back into the expression: 43×(2log32)=46log32=23log32
Both 43log34 and 23log32 are simplified forms of the expression.
The final answer is 43log34.
Explanation of the solution: The expression is simplified by first interpreting the symbol '|' as division. Then, standard logarithm properties such as the change of base formula (logbclogba=logca), power rule (logb(ak)=klogba), and identity (logbb=1) are applied to simplify each fractional term. The simplified terms are then combined using the arithmetic operations.