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Question: Ultraviolet light of wavelength 300 nm and intensity 1.0 watt/m<sup>2</sup> falls on the surface of ...

Ultraviolet light of wavelength 300 nm and intensity 1.0 watt/m2 falls on the surface of a photosensitive material. If 1% of the incident photons produce photoelectrons, then the number of photoelectrons emitted from an area of 1.0 cm2 of the surface is nearly –

A

9.61 × 1014 per sec

B

4.12 × 1013 per sec

C

1.51 × 1012 per sec

D

2.13 × 1011 per sec

Answer

1.51 × 1012 per sec

Explanation

Solution

ne = nc (nph)

= 1100\frac { 1 } { 100 } [5 × 1024 × 1 × 10–4 × 300 × 10–9]

= 15 × 1011 =1.5 × 1012/sec