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Question

Physics Question on Moving charges and magnetism

Two wires with currents 2A2\,A and 1A1\,A are enclosed in a circular loop. Another wire with current 3A3\, A is situated outside the loop as shown. Then B.dl\oint{\overrightarrow{B}}.\overrightarrow{dl} around the loop is

A

μ0{{\mu }_{0}}

B

3μ03{{\mu }_{0}}

C

6μ06{{\mu }_{0}}

D

2μ02{{\mu }_{0}}

Answer

μ0{{\mu }_{0}}

Explanation

Solution

Amperes law states that the line integral of B\overrightarrow{B} around any closed path or circuit is equal to μ0{{\mu }_{0}} times the total current crossing the area bounded by the closed path provided the electric field inside the loop remain constant. Thus,
B.dl=μ0inet\int{\overrightarrow{B}}.\overrightarrow{dl}={{\mu }_{0}}{{i}_{net}} =μ0(32)=μ0={{\mu }_{0}}(3-2)={{\mu }_{0}}