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Question: Two wires A and B of same length and of the same material have the respective radii r<sub>1</sub> an...

Two wires A and B of same length and of the same material have the respective radii r1 and r2. Their one end is fixed with a rigid support, and at the other end equal twisting couple is applied. Then the ratio of the angle of twist at the end of A and the angle of twist at the end of B will be

A

r12r22\frac{r_{1}^{2}}{r_{2}^{2}}

B

r22r12\frac{r_{2}^{2}}{r_{1}^{2}}

C

r24r14\frac{r_{2}^{4}}{r_{1}^{4}}

D

r14r24\frac{r_{1}^{4}}{r_{2}^{4}}

Answer

r24r14\frac{r_{2}^{4}}{r_{1}^{4}}

Explanation

Solution

τ1=τ2\tau_{1} = \tau_{2}πηr14θ12l1=πηr24θ22l2θ1θ2=(r2r1)4\frac{\pi\eta r_{1}^{4}\theta_{1}}{2l_{1}} = \frac{\pi\eta r_{2}^{4}\theta_{2}}{2l_{2}} \Rightarrow \frac{\theta_{1}}{\theta_{2}} = \left( \frac{r_{2}}{r_{1}} \right)^{4}