Question

Two waves are represented by the equations $y_1 = a \sin(\omega t + kx + 0.57) m$ and $y_2 = a \cos(\omega t + kx) m,$ where $x$ is in meter and $t$ in sec. The phase difference between them is

• A. 1.0 radian
• B. 1.25 radian
• C. 1.57 radian
• D. 0.57 radian

Answer 1

Answer: (A)

1.0 radian

Answer 2

$Y _{1}=$ asin $(\omega t + kx +0.57)$
$Y _{2}=$ asin $(\omega t + kx +\pi / 2)$
Phase difference $=\frac{\pi}{2}-0.57=1$ radian