Question

Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is 'a' and the phase of A is ahead by p/3 than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter –

• A. 2a
• B. a$\sqrt{3}$
• C. a$\sqrt{2}$
• D. a

Answer 1

Answer: (D)

a

Answer 2

Df = $\frac { 2 \pi } { \lambda }$ . Phase difference

̃ Df = p

R = = a