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Question

Physics Question on kinetic theory

Two vessels AA and BB having equal volume contain equal masses of hydrogen in AA and helium in BB at 300K300 \,K. Then, mark the correct statement.

A

The pressure exerted by hydrogen is half that exerted by helium

B

The pressure exerted by hydrogen is equal to that exerted by helium

C

Average KE of the molecule of hydrogen is half the average KE of the molecules of helium

D

The pressure exerted by hydrogen is twice that exerted by helium

Answer

The pressure exerted by hydrogen is twice that exerted by helium

Explanation

Solution

pV=nRTp V=n R T
pH2=mMH2RTVp_{H_{2}}=\frac{m}{M_{H_{2}}} \cdot \frac{R T}{V}
pHe=mMHeRTVp_{H e}=\frac{m}{M_{H e}} \cdot \frac{R T}{V}
PH2PHe=MHeMH2\therefore \frac{P_{H_{2}}}{P_{H e}}=\frac{M_{H e}}{M_{H_{2}}}
=4×1032×103=2=\frac{4 \times 10^{-3}}{2 \times 10^{-3}}=2
pH2=2PHe\Rightarrow p_{H_{2}}=2 P_{H e}