Question

Two very long straight, particle wires carry steady currents i and – i respectively. The distance between the wires is d. At a certain instant of time, a point charge q is at a point equidistant from the two wires, in the plane of the wires. It's instantaneous velocity $\vec { v }$ is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is

• A.
• B. $\frac { \mu _ { 0 } \mathrm { iqv } } { \pi \mathrm { d } }$
• C. $\frac { 2 \mu _ { 0 } \mathrm { iqv } } { \pi \mathrm { d } }$
• D. Zero

Answer 1

Answer: (D)

Zero

Answer 2

According to gives information following figure can be drawn, which shows that direction of magnetic field is along the direction of motion of charge so net on it is zero.