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Question

Physics Question on Moving charges and magnetism

Two very long, straight, and insulated wires are kept at 9090^{\circ} angle from each other in xyxy - plane as shown in the figure. These wires carry currents of equal magnitude II, whose directions are shown in the figure. The net magnetic field at point PP will be :

A

ZeroZero

B

+μ0Iπd(z^)\frac{+ \mu_{0}I}{\pi d} \left(\hat{z}\right)

C

μ0I2πd(x^+y^)- \frac{\mu_{0}I}{2\pi d} \left(\hat{x} +\hat{y}\right)

D

μ0I2πd(x^+y^)\frac{\mu_{0}I}{2\pi d} \left(\hat{x} + \hat{y}\right)

Answer

ZeroZero

Explanation

Solution

Magnetic field at point PP
Bnet=μ0i2πd(k^)+μ0i2πd(k^)=0\vec{B}_{net } = \frac{\mu_{0} i}{2\pi d} \left(-\hat{k}\right)+ \frac{\mu_{0} i}{2\pi d} \left(\hat{k}\right) = 0