Question

Two uniformly long charged wires with linear densities l and 3l are placed along X and Y axis respectively. Determined the slope of electric field at any point on the line y = $\sqrt{3}$x.

• A. 3$\sqrt{3}$
• B. $\frac{\sqrt{3}}{3\sqrt{2}}$
• C. $\frac{1}{3\sqrt{3}}$
• D. $\sqrt{3}$

Answer 1

Answer: (B)

$\frac{\sqrt{3}}{3\sqrt{2}}$

Answer 2

E = E₁ +E₂ + E₃ + E₄

The component of E₂ and E₃ along the line will cancel each other then

E = E₁ + E₄

The component perpendicular to BC will added up

AP =$\sqrt { \mathrm { AB } ^ { 2 } + \mathrm { BP } ^ { 2 } }$==

DP = cos q ===$\frac { 2 } { \sqrt { 5 } }$

\ E_P = E₁ cosq + E₄ cosq

= 2 ×.. $\frac { 2 } { \sqrt { 5 } }$=