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Question

Physics Question on simple harmonic motion

Two uniform strings of mass per unit length μ\mu and 4μ4\mu, and length LL and 2L2L, respectively, are joined at point OO, and tied at two fixed ends PP and QQ, as shown in the figure. The strings are under a uniform tension TT. If we define the frequency v0=12LTμv_0 = \frac{1}{2L} \sqrt{\frac{T}{\mu}}, which of the following statements is(are) correct?
Alternative_Text

A

With a node at OO, the minimum frequency of vibration of the composite string is v0v_0.

B

With an antinode at OO, the minimum frequency of vibration of the composite string is 2v02v_0.

C

When the composite string vibrates at the minimum frequency with a node at OO, it has 6 nodes, including the end nodes

D

No vibrational mode with an antinode at OO is possible for the composite string.

Answer

With a node at OO, the minimum frequency of vibration of the composite string is v0v_0.

Explanation

Solution

The correct option is (A): With a node at OO, the minimum frequency of vibration of the composite string is v0v_0.,(C): When the composite string vibrates at the minimum frequency with a node at OO, it has 6 nodes, including the end node and (D): No vibrational mode with an antinode at OO is possible for the composite string.