Solveeit Logo

Question

Physics Question on System of Particles & Rotational Motion

Two uniform circular discs are rotating independently in the same direction around their common axis passing through their centres. The moment of inertia and angular velocity of the first disc are 0.1kgm20.1\, kg - m ^{2} and 10rads110 \,rad\, s^{-1} respectively while those for the second one are 0.2kgm20.2\, kg - m ^{2} and 5rads15\, rad \,s ^{-1} respectively. At some instant they get stuck together and start rotating as a single system about their common axis with some angular speed. The Kinetic energy of the combined system is :

A

103J\frac{10}{3}\, J

B

23J\frac{2}{3}\, J

C

53J\frac{5}{3}\, J

D

203J\frac{20}{3} \,J

Answer

203J\frac{20}{3} \,J

Explanation

Solution

?? Both discs are rotating in same sense
?? Angular momentum conserved for the system
i.e. L1+L2=Lfinal \quad L_{1}+L_{2}=L_{\text {final }}
I1ω1+I2ω2=(I1+I2)ωfI _{1} \omega_{1}+ I _{2} \omega_{2}=\left( I _{1}+ I _{2}\right) \omega_{ f }
0.1×10+0.2×5=(0.1+0.2)×ωf0.1 \times 10+0.2 \times 5=(0.1+0.2) \times \omega_{ f }
ωf=203\omega_{ f }=\frac{20}{3}
?? Kinetic energy of combined disc system
12(I1+I2)ωf2\Rightarrow \frac{1}{2}\left( I _{1}+ I _{2}\right) \omega_{ f }^{2}
=12(0.1+0.2).(203)2=\frac{1}{2}(0.1+0.2) .\left(\frac{20}{3}\right)^{2}
=0.32×4009=12018=203J=\frac{0.3}{2} \times \frac{400}{9}=\frac{120}{18}=\frac{20}{3}\, J