Two unbiased six faced dice are thrown. The probability that... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

Two unbiased six faced dice are thrown. The probability that the sum of the numbers on their faces is a prime number greater than 5 is

A

$\frac{1}{6}$

B

$\frac{1}{2}$

C

$\frac{2}{9}$

D

$\frac{4}{9}$

Answer

$\frac{2}{9}$

Explanation

Solution

$P(7 + 11) = \frac{6 + 2}{36} = \frac{8}{36} = \frac{2}{9}$