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Question: Two trains, each 50 m long are travelling in opposite direction with velocity 10 m/s and 15 m/s. The...

Two trains, each 50 m long are travelling in opposite direction with velocity 10 m/s and 15 m/s. The time of crossing is

A

2s2s

B

4s4s

C

23s2\sqrt{3}s

D

t=ν1ν2at = \frac{\nu_{1} - \nu_{2}}{a}

Answer

4s4s

Explanation

Solution

Time=Total length Relative velocity =50+5010+15=10025=46musec= \frac{\text{Total length }}{\text{Relative velocity }} = \frac{50 + 50}{10 + 15} = \frac{100}{25} = 4\mspace{6mu}\sec