Solveeit Logo

Question

Question: Two trains \[A\] and \(B\) , are running on parallel tracks. One overtake the other in \(20s\) and o...

Two trains AA and BB , are running on parallel tracks. One overtake the other in 20s20s and one crosses the other in 10s10s . The velocity of the trains are
A.A. 5ms1,5ms15m{s^{ - 1}},5m{s^{ - 1}}
B.B. 10ms1,15ms110m{s^{ - 1}},15m{s^{ - 1}}
C.C. 15ms1,5ms115m{s^{ - 1}},5m{s^{ - 1}}
D.D. 15ms1,30ms115m{s^{ - 1}},30m{s^{ - 1}}

Explanation

Solution

This problem is based on relative velocity. Relative velocity is the velocity of one object with respect to the other object. If the two objects are moving in the opposite direction the relative velocity is obtained by adding the velocity of two objects (VAB=VA+VB)\left( {{V_{AB}} = {V_A} + {V_B}} \right) . When two objects are moving in the same direction the relative velocity is obtained by subtracting the velocity of two objects (VAB=VAVB)\left( {{V_{AB}} = {V_A} - {V_B}} \right)

Complete step-by-step solution:
Let uu and vv be the velocity of two trains AA and BB respectively
Total distance (S)\left( S \right) = Length of train AA + Length of train BB
S=100m+100m S=200m S = 100m + 100m \\\ S = 200m \\\
While overtaking, the two trains will travel in the same direction. Therefore relative velocity of train AA with respect to train BB is
VAB=uv{V_{AB}} = u - v
20020=uv\dfrac{{200}}{{20}} = u - v
Therefore, uv=10u - v = 10 ……….. (1)\left( 1 \right)
\Rightarrow While crossing, the two trains will travel in opposite directions. Therefore relative velocity of train AA with respect to train BB is
VAB=u+v{V_{AB}} = u + v
20010=u+v\dfrac{{200}}{{10}} = u + v
Therefore, u+v=20u + v = 20 ………(2)\left( 2 \right)
v=20uv = 20 - u ………. (3)\left( 3 \right)
Substituting equation (3)\left( 3 \right) in equation (1)\left( 1 \right) we get
u(20u)=10 u20+u=10 2u=30 u=302 u - \left( {20 - u} \right) = 10 \\\ u - 20 + u = 10 \\\ 2u = 30 \\\ u = \dfrac{{30}}{2} \\\
Therefore, u=15ms1u = 15m{s^{ - 1}}
Substituting equation (3)\left( 3 \right) in equation (1)\left( 1 \right)
15v=10 v=1510  15 - v = 10 \\\ v = 15 - 10 \\\
Therefore, v=5ms1v = 5m{s^{ - 1}}
\therefore Velocity of train AA is 15ms115m{s^{ - 1}}
Velocity of train AA is 5ms15m{s^{ - 1}}
Hence, Option CC is correct. That is 15ms1,5ms115m{s^{ - 1}},5m{s^{ - 1}}

Note: The difference between relative velocity and velocity is that relative velocity is measured in a frame where an object can be at rest or in motion with respect to the absolute frame. While the velocity is measured with respect to a reference point which is relative to a different point.